What would be the output of this code?

There are 2 different answer option(s) of this question, please select the right option(s).

int32_t nums[3]={2,4,3};
std::cout << ( nums[0] << nums[1] << nums[2] );

• The output is the addresses of nums[0], nums[1], and nums[2], in that order, with no spaces.
• 256
• 0
• 243

or

int i0=4, i1=6, i2=8;
int& nums[3]={i2,i0,i1};
std::cout<<nums[0]<<nums[1]<<nums[2];

• There is no output. The code causes a compiler error because nums is an array of references, which is illegal.
• 846
• The output is the addresses of i2, i0, and i1, in that order, with no spaces.
• 468